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Thursday, 30 October 2014

દ્વિપદી પ્રમેય

                                                 દ્વિપદી પ્રમેય


1. sum from r equals 0 to n of n C subscript r space space end subscript 4 to the power of r equals _ _ _ _ _ _ _ _ _ _


       A) 4 to the power of n
       B)5 to the power of n
           Right Answer
       C) 4 to the power of minus n end exponent
       D) 5 to the power of minus n end exponent


     Solution
    
              open parentheses 1 plus x close parentheses to the power of n equals sum from r equals 0 to n of space n space C subscript r space x to the power of r જેમાં x =4 મૂકતા 
open parentheses 1 plus 4 close parentheses to the power of n equals sum from r equals 0 to n of space n space C subscript 4 space 4 to the power of n


2.open parentheses 2 minus x cubed over 3 close parentheses to the power of 7 ના વિસ્તરણમાં પદ મધ્યમપદ  સહગુણક ......છે  ?


     A)minus 560 over 27 comma minus 280 over 81
     B) 560 over 27 begin inline style comma end style 280 over 81
     C)Syntax error from line 1 column 82 to line 1 column 87. Unexpected '</mo>'.       Right Answer
     D)560 over 27 begin inline style comma end style 280 over 81

      Solution


             n equals 7 હોવાથી fraction numerator 7 plus 3 over denominator 2 end fraction equals 4 અને fraction numerator 7 plus 3 over denominator 2 end fraction equals 5rightwards double arrow T subscript 4 અને T subscript 5 મધ્યમ પદ થશે 
હવે T subscript r plus 1 end subscript equals open parentheses table row n row r end table close parentheses a to the power of n minus r end exponent b to the power of r

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